Base | Representation |
---|---|
bin | 100110001011010110101… |
… | …0101000010000010000110 |
3 | 200120121120211210222000010 |
4 | 1030112231111002002012 |
5 | 1141431441114241014 |
6 | 15054244550531050 |
7 | 1051042053644526 |
oct | 114265525020206 |
9 | 20517524728003 |
10 | 5247063040134 |
11 | 17432a3328353 |
12 | 708aba966a86 |
13 | 2c0a46841586 |
14 | 141d600c1686 |
15 | 9174c79a359 |
hex | 4c5ad542086 |
5247063040134 has 32 divisors (see below), whose sum is σ = 10950788609280. Its totient is φ = 1672916094432.
The previous prime is 5247063040123. The next prime is 5247063040171. The reversal of 5247063040134 is 4310403607425.
It is a super-3 number, since 3×52470630401343 (a number of 39 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5247063040092 and 5247063040101.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3220524 + ... + 4567920.
It is an arithmetic number, because the mean of its divisors is an integer number (342212144040).
Almost surely, 25247063040134 is an apocalyptic number.
5247063040134 is an abundant number, since it is smaller than the sum of its proper divisors (5703725569146).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5247063040134 is a wasteful number, since it uses less digits than its factorization.
5247063040134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1375644.
The product of its (nonzero) digits is 241920, while the sum is 39.
Adding to 5247063040134 its reverse (4310403607425), we get a palindrome (9557466647559).
The spelling of 5247063040134 in words is "five trillion, two hundred forty-seven billion, sixty-three million, forty thousand, one hundred thirty-four".
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