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52501199963 is a prime number
BaseRepresentation
bin110000111001010100…
…001011110001011011
312000111220021021221112
4300321110023301123
51330010301344323
640041350530535
73536012556632
oct607124136133
9160456237845
1052501199963
11202a1616663
12a212666a4b
134c48ccc3c4
1427809b4519
15157425b178
hexc3950bc5b

52501199963 has 2 divisors, whose sum is σ = 52501199964. Its totient is φ = 52501199962.

The previous prime is 52501199939. The next prime is 52501200013. The reversal of 52501199963 is 36999110525.

52501199963 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an a-pointer prime, because the next prime (52501200013) can be obtained adding 52501199963 to its sum of digits (50).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 52501199963 - 26 = 52501199899 is a prime.

It is a super-2 number, since 2×525011999632 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (52501199903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26250599981 + 26250599982.

It is an arithmetic number, because the mean of its divisors is an integer number (26250599982).

Almost surely, 252501199963 is an apocalyptic number.

52501199963 is a deficient number, since it is larger than the sum of its proper divisors (1).

52501199963 is an equidigital number, since it uses as much as digits as its factorization.

52501199963 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 656100, while the sum is 50.

The spelling of 52501199963 in words is "fifty-two billion, five hundred one million, one hundred ninety-nine thousand, nine hundred sixty-three".