Base | Representation |
---|---|
bin | 110000111001100010… |
… | …110000100100110011 |
3 | 12000112011110102001011 |
4 | 300321202300210303 |
5 | 1330012241130343 |
6 | 40042004451351 |
7 | 3536060212111 |
oct | 607142604463 |
9 | 160464412034 |
10 | 52505020723 |
11 | 202a3796211 |
12 | a2139a9b57 |
13 | 4c49a394cc |
14 | 27812caab1 |
15 | 157476329d |
hex | c398b0933 |
52505020723 has 2 divisors, whose sum is σ = 52505020724. Its totient is φ = 52505020722.
The previous prime is 52505020721. The next prime is 52505020759. The reversal of 52505020723 is 32702050525.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 52505020723 - 21 = 52505020721 is a prime.
It is a super-3 number, since 3×525050207233 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 52505020721, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (52505020721) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26252510361 + 26252510362.
It is an arithmetic number, because the mean of its divisors is an integer number (26252510362).
Almost surely, 252505020723 is an apocalyptic number.
52505020723 is a deficient number, since it is larger than the sum of its proper divisors (1).
52505020723 is an equidigital number, since it uses as much as digits as its factorization.
52505020723 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21000, while the sum is 31.
The spelling of 52505020723 in words is "fifty-two billion, five hundred five million, twenty thousand, seven hundred twenty-three".
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