Base | Representation |
---|---|
bin | 100110001100111110101… |
… | …1101111111100000010011 |
3 | 200120221121012122102222222 |
4 | 1030121331131333200103 |
5 | 1142011114043100003 |
6 | 15100023252451255 |
7 | 1051224435355364 |
oct | 114317535774023 |
9 | 20527535572888 |
10 | 5250555050003 |
11 | 174482549801a |
12 | 709714319b2b |
13 | 2c11821410c3 |
14 | 1421b1b9db6b |
15 | 918a4129c38 |
hex | 4c67d77f813 |
5250555050003 has 2 divisors, whose sum is σ = 5250555050004. Its totient is φ = 5250555050002.
The previous prime is 5250555049997. The next prime is 5250555050009. The reversal of 5250555050003 is 3000505550525.
It is a balanced prime because it is at equal distance from previous prime (5250555049997) and next prime (5250555050009).
It is a cyclic number.
It is not a de Polignac number, because 5250555050003 - 210 = 5250555048979 is a prime.
It is a super-2 number, since 2×52505550500032 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5250555050009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2625277525001 + 2625277525002.
It is an arithmetic number, because the mean of its divisors is an integer number (2625277525002).
Almost surely, 25250555050003 is an apocalyptic number.
5250555050003 is a deficient number, since it is larger than the sum of its proper divisors (1).
5250555050003 is an equidigital number, since it uses as much as digits as its factorization.
5250555050003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 93750, while the sum is 35.
The spelling of 5250555050003 in words is "five trillion, two hundred fifty billion, five hundred fifty-five million, fifty thousand, three".
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