52511341133 has 2 divisors, whose sum is σ = 52511341134. Its totient is φ = 52511341132.

The previous prime is 52511341081. The next prime is 52511341151. The reversal of 52511341133 is 33114311525.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47767162249 + 4744178884 = 218557^2 + 68878^2 .

It is a cyclic number.

It is not a de Polignac number, because 52511341133 - 2²⁰ = 52510292557 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 52511341096 and 52511341105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (52511341153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26255670566 + 26255670567.

It is an arithmetic number, because the mean of its divisors is an integer number (26255670567).

Almost surely, 2^52511341133 is an apocalyptic number.

It is an amenable number.

52511341133 is a deficient number, since it is larger than the sum of its proper divisors (1).

52511341133 is an equidigital number, since it uses as much as digits as its factorization.

52511341133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5400, while the sum is 29.

Adding to 52511341133 its reverse (33114311525), we get a palindrome (85625652658).

The spelling of 52511341133 in words is "fifty-two billion, five hundred eleven million, three hundred forty-one thousand, one hundred thirty-three".