Base | Representation |
---|---|
bin | 100110001101010000101… |
… | …0001011100001101001111 |
3 | 200121000011001221122001001 |
4 | 1030122201101130031033 |
5 | 1142013331332130341 |
6 | 15100203031401131 |
7 | 1051245351215545 |
oct | 114324121341517 |
9 | 20530131848031 |
10 | 5251155739471 |
11 | 17450035769a4 |
12 | 7098615231a7 |
13 | 2c124971b765 |
14 | 14222b885d95 |
15 | 918dbc31d31 |
hex | 4c6a145c34f |
5251155739471 has 2 divisors, whose sum is σ = 5251155739472. Its totient is φ = 5251155739470.
The previous prime is 5251155739393. The next prime is 5251155739483. The reversal of 5251155739471 is 1749375511525.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5251155739471 - 217 = 5251155608399 is a prime.
It is a super-3 number, since 3×52511557394713 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5251155733471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2625577869735 + 2625577869736.
It is an arithmetic number, because the mean of its divisors is an integer number (2625577869736).
Almost surely, 25251155739471 is an apocalyptic number.
5251155739471 is a deficient number, since it is larger than the sum of its proper divisors (1).
5251155739471 is an equidigital number, since it uses as much as digits as its factorization.
5251155739471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6615000, while the sum is 55.
The spelling of 5251155739471 in words is "five trillion, two hundred fifty-one billion, one hundred fifty-five million, seven hundred thirty-nine thousand, four hundred seventy-one".
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