Base | Representation |
---|---|
bin | 110000111010000001… |
… | …100110001000100101 |
3 | 12000112201200002210101 |
4 | 300322001212020211 |
5 | 1330021323320141 |
6 | 40042454024101 |
7 | 3536216010541 |
oct | 607201461045 |
9 | 160481602711 |
10 | 52513104421 |
11 | 202a8307658 |
12 | a216648031 |
13 | 4c4b609a6b |
14 | 27823d2a21 |
15 | 157530d531 |
hex | c3a066225 |
52513104421 has 2 divisors, whose sum is σ = 52513104422. Its totient is φ = 52513104420.
The previous prime is 52513104331. The next prime is 52513104433. The reversal of 52513104421 is 12440131525.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 52509722500 + 3381921 = 229150^2 + 1839^2 .
It is a cyclic number.
It is not a de Polignac number, because 52513104421 - 217 = 52512973349 is a prime.
It is a super-2 number, since 2×525131044212 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 52513104421.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52513104461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26256552210 + 26256552211.
It is an arithmetic number, because the mean of its divisors is an integer number (26256552211).
Almost surely, 252513104421 is an apocalyptic number.
It is an amenable number.
52513104421 is a deficient number, since it is larger than the sum of its proper divisors (1).
52513104421 is an equidigital number, since it uses as much as digits as its factorization.
52513104421 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4800, while the sum is 28.
Adding to 52513104421 its reverse (12440131525), we get a palindrome (64953235946).
The spelling of 52513104421 in words is "fifty-two billion, five hundred thirteen million, one hundred four thousand, four hundred twenty-one".
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