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5251383653 is a prime number
BaseRepresentation
bin1001110010000000…
…11100000101100101
3111112222101221002212
410321000130011211
541223323234103
62225031213205
7244064011265
oct47100340545
914488357085
105251383653
1122552a629a
121026817205
13658c67009
1437b61b7a5
1520b0607d8
hex13901c165

5251383653 has 2 divisors, whose sum is σ = 5251383654. Its totient is φ = 5251383652.

The previous prime is 5251383611. The next prime is 5251383659. The reversal of 5251383653 is 3563831525.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3924020164 + 1327363489 = 62642^2 + 36433^2 .

It is a cyclic number.

It is not a de Polignac number, because 5251383653 - 226 = 5184274789 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5251383653.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5251383659) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2625691826 + 2625691827.

It is an arithmetic number, because the mean of its divisors is an integer number (2625691827).

Almost surely, 25251383653 is an apocalyptic number.

It is an amenable number.

5251383653 is a deficient number, since it is larger than the sum of its proper divisors (1).

5251383653 is an equidigital number, since it uses as much as digits as its factorization.

5251383653 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 324000, while the sum is 41.

The square root of 5251383653 is about 72466.4312147356. The cubic root of 5251383653 is about 1738.1659952124.

The spelling of 5251383653 in words is "five billion, two hundred fifty-one million, three hundred eighty-three thousand, six hundred fifty-three".