Base | Representation |
---|---|
bin | 10111111000011011010000… |
… | …01100001001011110100111 |
3 | 20212221111210011021100212121 |
4 | 23330031220030021132213 |
5 | 23340411402131040312 |
6 | 303405354452530411 |
7 | 14030115124266034 |
oct | 1374155014113647 |
9 | 225844704240777 |
10 | 52516313143207 |
11 | 15808052743301 |
12 | 5a8201b020a07 |
13 | 233c361a0b574 |
14 | cd7b35a8438b |
15 | 61110a9be707 |
hex | 2fc3683097a7 |
52516313143207 has 2 divisors, whose sum is σ = 52516313143208. Its totient is φ = 52516313143206.
The previous prime is 52516313143157. The next prime is 52516313143219. The reversal of 52516313143207 is 70234131361525.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 52516313143207 - 243 = 43720220120999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52516313143247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26258156571603 + 26258156571604.
It is an arithmetic number, because the mean of its divisors is an integer number (26258156571604).
Almost surely, 252516313143207 is an apocalyptic number.
52516313143207 is a deficient number, since it is larger than the sum of its proper divisors (1).
52516313143207 is an equidigital number, since it uses as much as digits as its factorization.
52516313143207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 453600, while the sum is 43.
The spelling of 52516313143207 in words is "fifty-two trillion, five hundred sixteen billion, three hundred thirteen million, one hundred forty-three thousand, two hundred seven".
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