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525216384013 is a prime number
BaseRepresentation
bin1111010010010010101…
…01100000010000001101
31212012200020021202010011
413221021111200100031
532101120343242023
61041140413513221
752642231414036
oct7511125402015
91765606252104
10525216384013
11192819a57a92
1285959aa2811
133a6b2456b69
141b5c6215a8d
15d9de7e950d
hex7a4956040d

525216384013 has 2 divisors, whose sum is σ = 525216384014. Its totient is φ = 525216384012.

The previous prime is 525216383999. The next prime is 525216384019. The reversal of 525216384013 is 310483612525.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 489750831684 + 35465552329 = 699822^2 + 188323^2 .

It is a cyclic number.

It is not a de Polignac number, because 525216384013 - 25 = 525216383981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (525216384019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 262608192006 + 262608192007.

It is an arithmetic number, because the mean of its divisors is an integer number (262608192007).

Almost surely, 2525216384013 is an apocalyptic number.

It is an amenable number.

525216384013 is a deficient number, since it is larger than the sum of its proper divisors (1).

525216384013 is an equidigital number, since it uses as much as digits as its factorization.

525216384013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 172800, while the sum is 40.

Adding to 525216384013 its reverse (310483612525), we get a palindrome (835699996538).

The spelling of 525216384013 in words is "five hundred twenty-five billion, two hundred sixteen million, three hundred eighty-four thousand, thirteen".