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5253412433 is a prime number
BaseRepresentation
bin1001110010010000…
…01011011001010001
3111120010020000001212
410321020023121101
541224333144213
62225142505505
7244120161143
oct47110133121
914503200055
105253412433
112256461575
121027435295
136594c7589
1437b9c8c93
1520b3119a8
hex13920b651

5253412433 has 2 divisors, whose sum is σ = 5253412434. Its totient is φ = 5253412432.

The previous prime is 5253412397. The next prime is 5253412487. The reversal of 5253412433 is 3342143525.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3892761664 + 1360650769 = 62392^2 + 36887^2 .

It is a cyclic number.

It is not a de Polignac number, because 5253412433 - 210 = 5253411409 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5253412433.

It is not a weakly prime, because it can be changed into another prime (5253412133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2626706216 + 2626706217.

It is an arithmetic number, because the mean of its divisors is an integer number (2626706217).

Almost surely, 25253412433 is an apocalyptic number.

It is an amenable number.

5253412433 is a deficient number, since it is larger than the sum of its proper divisors (1).

5253412433 is an equidigital number, since it uses as much as digits as its factorization.

5253412433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 43200, while the sum is 32.

The square root of 5253412433 is about 72480.4279305800. The cubic root of 5253412433 is about 1738.3898030455.

Adding to 5253412433 its reverse (3342143525), we get a palindrome (8595555958).

The spelling of 5253412433 in words is "five billion, two hundred fifty-three million, four hundred twelve thousand, four hundred thirty-three".