Base | Representation |
---|---|
bin | 10111111000111100110100… |
… | …10001110000011100100101 |
3 | 20220000020022000110101112012 |
4 | 23330132122101300130211 |
5 | 23341210303313443100 |
6 | 303421534540204005 |
7 | 14031323516413145 |
oct | 1374363221603445 |
9 | 226006260411465 |
10 | 52534333343525 |
11 | 1581475a672540 |
12 | 5a85609b39605 |
13 | 2340c741924a7 |
14 | cd896504c925 |
15 | 611812a18135 |
hex | 2fc79a470725 |
52534333343525 has 24 divisors (see below), whose sum is σ = 71065013402208. Its totient is φ = 38206579320000.
The previous prime is 52534333343497. The next prime is 52534333343603.
52534333343525 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 52534333343525 - 236 = 52465613866789 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 64797155 + ... + 65602895.
It is an arithmetic number, because the mean of its divisors is an integer number (2961042225092).
Almost surely, 252534333343525 is an apocalyptic number.
52534333343525 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
52534333343525 is a deficient number, since it is larger than the sum of its proper divisors (18530680058683).
52534333343525 is a wasteful number, since it uses less digits than its factorization.
52534333343525 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1042853 (or 1042848 counting only the distinct ones).
The product of its digits is 29160000, while the sum is 50.
It can be divided in two parts, 5253433 and 3343525, that added together give a palindrome (8596958).
The spelling of 52534333343525 in words is "fifty-two trillion, five hundred thirty-four billion, three hundred thirty-three million, three hundred forty-three thousand, five hundred twenty-five".
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