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52540044133 is a prime number
BaseRepresentation
bin110000111011101000…
…010111001101100101
312000121121100210010111
4300323220113031211
51330100222403013
640045255253021
73536664002143
oct607350271545
9160547323114
1052540044133
1120311537885
12a22367a171
134c5407cb15
142785c06593
15157788073d
hexc3ba17365

52540044133 has 2 divisors, whose sum is σ = 52540044134. Its totient is φ = 52540044132.

The previous prime is 52540044119. The next prime is 52540044197. The reversal of 52540044133 is 33144004525.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 33314280484 + 19225763649 = 182522^2 + 138657^2 .

It is a cyclic number.

It is not a de Polignac number, because 52540044133 - 213 = 52540035941 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 52540044095 and 52540044104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (52540041133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26270022066 + 26270022067.

It is an arithmetic number, because the mean of its divisors is an integer number (26270022067).

Almost surely, 252540044133 is an apocalyptic number.

It is an amenable number.

52540044133 is a deficient number, since it is larger than the sum of its proper divisors (1).

52540044133 is an equidigital number, since it uses as much as digits as its factorization.

52540044133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 52540044133 its reverse (33144004525), we get a palindrome (85684048658).

The spelling of 52540044133 in words is "fifty-two billion, five hundred forty million, forty-four thousand, one hundred thirty-three".