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5254014700000 = 25551141971201
BaseRepresentation
bin100110001110100101110…
…1011100000100111100000
3200121021112022120212121001
41030131023223200213200
51142040210230400000
615101354441041344
71051406245041463
oct114351353404740
920537468525531
105254014700000
1117462403652a0
1270a31aa86254
132c15b3b20791
1414241d4572da
1591a07c1646a
hex4c74bae09e0

5254014700000 has 576 divisors, whose sum is σ = 14609450060352. Its totient is φ = 1843200000000.

The previous prime is 5254014699979. The next prime is 5254014700019. The reversal of 5254014700000 is 74104525.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 4374699400 + ... + 4374700600.

It is an arithmetic number, because the mean of its divisors is an integer number (25363628577).

Almost surely, 25254014700000 is an apocalyptic number.

5254014700000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 5254014700000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (7304725030176).

5254014700000 is an abundant number, since it is smaller than the sum of its proper divisors (9355435360352).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

5254014700000 is a wasteful number, since it uses less digits than its factorization.

5254014700000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1385 (or 1357 counting only the distinct ones).

The product of its (nonzero) digits is 5600, while the sum is 28.

Adding to 5254014700000 its reverse (74104525), we get a palindrome (5254088804525).

The spelling of 5254014700000 in words is "five trillion, two hundred fifty-four billion, fourteen million, seven hundred thousand".