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5254114603 is a prime number
BaseRepresentation
bin1001110010010101…
…10110110100101011
3111120011112200021011
410321022312310223
541230023131403
62225205524351
7244126144243
oct47112666453
914504480234
105254114603
1122568a1081
1210277136b7
136596b206a
1437bb2cb23
1520b3eea6d
hex1392b6d2b

5254114603 has 2 divisors, whose sum is σ = 5254114604. Its totient is φ = 5254114602.

The previous prime is 5254114597. The next prime is 5254114693. The reversal of 5254114603 is 3064114525.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5254114603 is a prime.

It is a super-2 number, since 2×52541146032 = 55211440522915695218, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5254114693) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2627057301 + 2627057302.

It is an arithmetic number, because the mean of its divisors is an integer number (2627057302).

Almost surely, 25254114603 is an apocalyptic number.

5254114603 is a deficient number, since it is larger than the sum of its proper divisors (1).

5254114603 is an equidigital number, since it uses as much as digits as its factorization.

5254114603 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 31.

The square root of 5254114603 is about 72485.2716281039. The cubic root of 5254114603 is about 1738.4672505335.

The spelling of 5254114603 in words is "five billion, two hundred fifty-four million, one hundred fourteen thousand, six hundred three".