Base | Representation |
---|---|
bin | 10111111001001111111000… |
… | …01001010100110110101101 |
3 | 20220001012201002120100010001 |
4 | 23330213330021110312231 |
5 | 23341342232200010432 |
6 | 303430350125144301 |
7 | 14032135211146654 |
oct | 1374477411246655 |
9 | 226035632510101 |
10 | 52544565235117 |
11 | 1581903027209a |
12 | 5a875a46bb091 |
13 | 2341c14c21c07 |
14 | cd9255cd619b |
15 | 611c10e2e9e7 |
hex | 2fc9fc254dad |
52544565235117 has 2 divisors, whose sum is σ = 52544565235118. Its totient is φ = 52544565235116.
The previous prime is 52544565235111. The next prime is 52544565235139. The reversal of 52544565235117 is 71153256544525.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52281489592836 + 263075642281 = 7230594^2 + 512909^2 .
It is a cyclic number.
It is not a de Polignac number, because 52544565235117 - 231 = 52542417751469 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52544565235111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26272282617558 + 26272282617559.
It is an arithmetic number, because the mean of its divisors is an integer number (26272282617559).
Almost surely, 252544565235117 is an apocalyptic number.
It is an amenable number.
52544565235117 is a deficient number, since it is larger than the sum of its proper divisors (1).
52544565235117 is an equidigital number, since it uses as much as digits as its factorization.
52544565235117 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 25200000, while the sum is 55.
The spelling of 52544565235117 in words is "fifty-two trillion, five hundred forty-four billion, five hundred sixty-five million, two hundred thirty-five thousand, one hundred seventeen".
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