Base | Representation |
---|---|
bin | 10111111001001111111000… |
… | …01001010100110111001011 |
3 | 20220001012201002120100011011 |
4 | 23330213330021110313023 |
5 | 23341342232200011042 |
6 | 303430350125144351 |
7 | 14032135211150026 |
oct | 1374477411246713 |
9 | 226035632510134 |
10 | 52544565235147 |
11 | 15819030272117 |
12 | 5a875a46bb0b7 |
13 | 2341c14c21c2b |
14 | cd9255cd61bd |
15 | 611c10e2ea17 |
hex | 2fc9fc254dcb |
52544565235147 has 2 divisors, whose sum is σ = 52544565235148. Its totient is φ = 52544565235146.
The previous prime is 52544565235139. The next prime is 52544565235159. The reversal of 52544565235147 is 74153256544525.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 52544565235147 - 23 = 52544565235139 is a prime.
It is a super-2 number, since 2×525445652351472 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 52544565235091 and 52544565235100.
It is not a weakly prime, because it can be changed into another prime (52544565235117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26272282617573 + 26272282617574.
It is an arithmetic number, because the mean of its divisors is an integer number (26272282617574).
Almost surely, 252544565235147 is an apocalyptic number.
52544565235147 is a deficient number, since it is larger than the sum of its proper divisors (1).
52544565235147 is an equidigital number, since it uses as much as digits as its factorization.
52544565235147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 100800000, while the sum is 58.
The spelling of 52544565235147 in words is "fifty-two trillion, five hundred forty-four billion, five hundred sixty-five million, two hundred thirty-five thousand, one hundred forty-seven".
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