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525471400100749 is a prime number
BaseRepresentation
bin111011101111010011101100…
…0001001001000001110001101
32112220112120112100121120112011
41313132213120021020032031
51022333310411411210444
65101330121220341221
7215453025102465004
oct16736473011101615
92486476470546464
10525471400100749
11142482195389193
124ab27a64844811
13197289818a9c2b
1493a8d46b75c3b
1540b3ab4d74734
hex1dde9d824838d

525471400100749 has 2 divisors, whose sum is σ = 525471400100750. Its totient is φ = 525471400100748.

The previous prime is 525471400100719. The next prime is 525471400100869. The reversal of 525471400100749 is 947001004174525.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 370094103108900 + 155377296991849 = 19237830^2 + 12465043^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-525471400100749 is a prime.

It is a super-2 number, since 2×5254714001007492 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (525471400100719) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 262735700050374 + 262735700050375.

It is an arithmetic number, because the mean of its divisors is an integer number (262735700050375).

Almost surely, 2525471400100749 is an apocalyptic number.

It is an amenable number.

525471400100749 is a deficient number, since it is larger than the sum of its proper divisors (1).

525471400100749 is an equidigital number, since it uses as much as digits as its factorization.

525471400100749 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1411200, while the sum is 49.

The spelling of 525471400100749 in words is "five hundred twenty-five trillion, four hundred seventy-one billion, four hundred million, one hundred thousand, seven hundred forty-nine".