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5265743292893 is a prime number
BaseRepresentation
bin100110010100000011011…
…0000100010100111011101
3200122101210201000010101102
41030220012300202213131
51142233220240333033
615111014333322445
71052303012324036
oct114500660424735
920571721003342
105265743292893
1117502098a1776
12710652936425
132c2732988b85
14142c12dc5a8d
1591e92724de8
hex4ca06c229dd

5265743292893 has 2 divisors, whose sum is σ = 5265743292894. Its totient is φ = 5265743292892.

The previous prime is 5265743292791. The next prime is 5265743292917. The reversal of 5265743292893 is 3982923475625.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4511282544484 + 754460748409 = 2123978^2 + 868597^2 .

It is a cyclic number.

It is not a de Polignac number, because 5265743292893 - 210 = 5265743291869 is a prime.

It is a super-3 number, since 3×52657432928933 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5265740292893) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2632871646446 + 2632871646447.

It is an arithmetic number, because the mean of its divisors is an integer number (2632871646447).

Almost surely, 25265743292893 is an apocalyptic number.

It is an amenable number.

5265743292893 is a deficient number, since it is larger than the sum of its proper divisors (1).

5265743292893 is an equidigital number, since it uses as much as digits as its factorization.

5265743292893 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 195955200, while the sum is 65.

The spelling of 5265743292893 in words is "five trillion, two hundred sixty-five billion, seven hundred forty-three million, two hundred ninety-two thousand, eight hundred ninety-three".