Base | Representation |
---|---|
bin | 100110010100011101001… |
… | …1110101111101111101011 |
3 | 200122111001011211102011122 |
4 | 1030220322132233233223 |
5 | 1142242004411341212 |
6 | 15111240412245455 |
7 | 1052333350144445 |
oct | 114507236575753 |
9 | 20574034742148 |
10 | 5266611043307 |
11 | 17506146a7479 |
12 | 71085547088b |
13 | 2c28406a0663 |
14 | 142c96349495 |
15 | 91ee39d1272 |
hex | 4ca3a7afbeb |
5266611043307 has 2 divisors, whose sum is σ = 5266611043308. Its totient is φ = 5266611043306.
The previous prime is 5266611043301. The next prime is 5266611043403. The reversal of 5266611043307 is 7033401166625.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5266611043307 - 212 = 5266611039211 is a prime.
It is not a weakly prime, because it can be changed into another prime (5266611043301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2633305521653 + 2633305521654.
It is an arithmetic number, because the mean of its divisors is an integer number (2633305521654).
Almost surely, 25266611043307 is an apocalyptic number.
5266611043307 is a deficient number, since it is larger than the sum of its proper divisors (1).
5266611043307 is an equidigital number, since it uses as much as digits as its factorization.
5266611043307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 544320, while the sum is 44.
The spelling of 5266611043307 in words is "five trillion, two hundred sixty-six billion, six hundred eleven million, forty-three thousand, three hundred seven".
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