Base | Representation |
---|---|
bin | 100110010100011101001… |
… | …1110101111110001001011 |
3 | 200122111001011211102022012 |
4 | 1030220322132233301023 |
5 | 1142242004411342103 |
6 | 15111240412250135 |
7 | 1052333350144643 |
oct | 114507236576113 |
9 | 20574034742265 |
10 | 5266611043403 |
11 | 17506146a7556 |
12 | 71085547094b |
13 | 2c28406a0708 |
14 | 142c96349523 |
15 | 91ee39d12d8 |
hex | 4ca3a7afc4b |
5266611043403 has 2 divisors, whose sum is σ = 5266611043404. Its totient is φ = 5266611043402.
The previous prime is 5266611043307. The next prime is 5266611043417. The reversal of 5266611043403 is 3043401166625.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5266611043403 - 28 = 5266611043147 is a prime.
It is not a weakly prime, because it can be changed into another prime (5266611043433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2633305521701 + 2633305521702.
It is an arithmetic number, because the mean of its divisors is an integer number (2633305521702).
Almost surely, 25266611043403 is an apocalyptic number.
5266611043403 is a deficient number, since it is larger than the sum of its proper divisors (1).
5266611043403 is an equidigital number, since it uses as much as digits as its factorization.
5266611043403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 41.
The spelling of 5266611043403 in words is "five trillion, two hundred sixty-six billion, six hundred eleven million, forty-three thousand, four hundred three".
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