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52678409201317 is a prime number
BaseRepresentation
bin10111111101001001001011…
…10111100010011010100101
320220112000011220121022001101
423332210211313202122211
523401040340223420232
6304012043242000101
714044614042120604
oct1376444567423245
9226460156538041
1052678409201317
111586a873741999
125aa95187a6031
1323517252b5a53
14d01911ad9a3b
156154464961e7
hex2fe925de26a5

52678409201317 has 2 divisors, whose sum is σ = 52678409201318. Its totient is φ = 52678409201316.

The previous prime is 52678409201311. The next prime is 52678409201441. The reversal of 52678409201317 is 71310290487625.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 49319073744516 + 3359335456801 = 7022754^2 + 1832849^2 .

It is a cyclic number.

It is not a de Polignac number, because 52678409201317 - 219 = 52678408677029 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (52678409201311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26339204600658 + 26339204600659.

It is an arithmetic number, because the mean of its divisors is an integer number (26339204600659).

It is a 1-persistent number, because it is pandigital, but 2⋅52678409201317 = 105356818402634 is not.

Almost surely, 252678409201317 is an apocalyptic number.

It is an amenable number.

52678409201317 is a deficient number, since it is larger than the sum of its proper divisors (1).

52678409201317 is an equidigital number, since it uses as much as digits as its factorization.

52678409201317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5080320, while the sum is 55.

The spelling of 52678409201317 in words is "fifty-two trillion, six hundred seventy-eight billion, four hundred nine million, two hundred one thousand, three hundred seventeen".