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5280433 is a prime number
BaseRepresentation
bin10100001001001010110001
3100221021101121
4110021022301
52322433213
6305102241
762611564
oct24111261
910837347
105280433
112a872a4
121927981
13112b622
149b64db
156e488d
hex5092b1

5280433 has 2 divisors, whose sum is σ = 5280434. Its totient is φ = 5280432.

The previous prime is 5280427. The next prime is 5280437. The reversal of 5280433 is 3340825.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3869089 + 1411344 = 1967^2 + 1188^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5280433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5280398 and 5280407.

It is not a weakly prime, because it can be changed into another prime (5280437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2640216 + 2640217.

It is an arithmetic number, because the mean of its divisors is an integer number (2640217).

Almost surely, 25280433 is an apocalyptic number.

It is an amenable number.

5280433 is a deficient number, since it is larger than the sum of its proper divisors (1).

5280433 is an equidigital number, since it uses as much as digits as its factorization.

5280433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 25.

The square root of 5280433 is about 2297.9192762149. The cubic root of 5280433 is about 174.1365137344.

The spelling of 5280433 in words is "five million, two hundred eighty thousand, four hundred thirty-three".