Base | Representation |
---|---|
bin | 1001110111000110… |
… | …10000111011101001 |
3 | 111122221201111020121 |
4 | 10323203100323221 |
5 | 41320240124213 |
6 | 2233154123241 |
7 | 245122554634 |
oct | 47343207351 |
9 | 14587644217 |
10 | 5294067433 |
11 | 22773aa246 |
12 | 1038b80521 |
13 | 664a602a5 |
14 | 38316cc1b |
15 | 20eb9288d |
hex | 13b8d0ee9 |
5294067433 has 2 divisors, whose sum is σ = 5294067434. Its totient is φ = 5294067432.
The previous prime is 5294067431. The next prime is 5294067491. The reversal of 5294067433 is 3347604925.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3468385449 + 1825681984 = 58893^2 + 42728^2 .
It is a cyclic number.
It is not a de Polignac number, because 5294067433 - 21 = 5294067431 is a prime.
Together with 5294067431, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 5294067433.
It is not a weakly prime, because it can be changed into another prime (5294067431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2647033716 + 2647033717.
It is an arithmetic number, because the mean of its divisors is an integer number (2647033717).
Almost surely, 25294067433 is an apocalyptic number.
It is an amenable number.
5294067433 is a deficient number, since it is larger than the sum of its proper divisors (1).
5294067433 is an equidigital number, since it uses as much as digits as its factorization.
5294067433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 544320, while the sum is 43.
The square root of 5294067433 is about 72760.3424469676. The cubic root of 5294067433 is about 1742.8626231636.
The spelling of 5294067433 in words is "five billion, two hundred ninety-four million, sixty-seven thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •