Base | Representation |
---|---|
bin | 110001010111000011… |
… | …011001001011000111 |
3 | 12001210200001210120001 |
4 | 301113003121023013 |
5 | 1332021012134022 |
6 | 40203052222131 |
7 | 3554251354246 |
oct | 612703311307 |
9 | 161720053501 |
10 | 53000114887 |
11 | 20528201845 |
12 | a33176a947 |
13 | 4cc8494635 |
14 | 27cad6695d |
15 | 15a2e5cb27 |
hex | c570d92c7 |
53000114887 has 2 divisors, whose sum is σ = 53000114888. Its totient is φ = 53000114886.
The previous prime is 53000114879. The next prime is 53000114911. The reversal of 53000114887 is 78841100035.
53000114887 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53000114887 - 23 = 53000114879 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53000114857) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26500057443 + 26500057444.
It is an arithmetic number, because the mean of its divisors is an integer number (26500057444).
Almost surely, 253000114887 is an apocalyptic number.
53000114887 is a deficient number, since it is larger than the sum of its proper divisors (1).
53000114887 is an equidigital number, since it uses as much as digits as its factorization.
53000114887 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26880, while the sum is 37.
The spelling of 53000114887 in words is "fifty-three billion, one hundred fourteen thousand, eight hundred eighty-seven".
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