Base | Representation |
---|---|
bin | 110001010111000011… |
… | …011001001101001011 |
3 | 12001210200001210201221 |
4 | 301113003121031023 |
5 | 1332021012140034 |
6 | 40203052222511 |
7 | 3554251354525 |
oct | 612703311513 |
9 | 161720053657 |
10 | 53000115019 |
11 | 20528201955 |
12 | a33176aa37 |
13 | 4cc8494707 |
14 | 27cad66a15 |
15 | 15a2e5cbb4 |
hex | c570d934b |
53000115019 has 2 divisors, whose sum is σ = 53000115020. Its totient is φ = 53000115018.
The previous prime is 53000115001. The next prime is 53000115023. The reversal of 53000115019 is 91051100035.
53000115019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53000115019 - 215 = 53000082251 is a prime.
It is a super-2 number, since 2×530001150192 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 53000114984 and 53000115002.
It is not a weakly prime, because it can be changed into another prime (53000115919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26500057509 + 26500057510.
It is an arithmetic number, because the mean of its divisors is an integer number (26500057510).
Almost surely, 253000115019 is an apocalyptic number.
53000115019 is a deficient number, since it is larger than the sum of its proper divisors (1).
53000115019 is an equidigital number, since it uses as much as digits as its factorization.
53000115019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 675, while the sum is 25.
The spelling of 53000115019 in words is "fifty-three billion, one hundred fifteen thousand, nineteen".
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