Search a number
-
+
530010550203353 is a prime number
BaseRepresentation
bin111100010000010101011001…
…0100100100111001111011001
32120111121111212112100021010222
41320200222302210213033121
51023432143101323001403
65115123252504245425
7216431666343655352
oct17040526244471731
92514544775307128
10530010550203353
1114397223727484a
124b53b718a70875
1319997a1b7a22cb
1494c490ca6cd29
154141bcda18338
hex1e20ab29273d9

530010550203353 has 2 divisors, whose sum is σ = 530010550203354. Its totient is φ = 530010550203352.

The previous prime is 530010550203319. The next prime is 530010550203391. The reversal of 530010550203353 is 353302055010035.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 476690718229504 + 53319831973849 = 21833248^2 + 7302043^2 .

It is a cyclic number.

It is not a de Polignac number, because 530010550203353 - 26 = 530010550203289 is a prime.

It is a super-2 number, since 2×5300105502033532 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (530010550200353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265005275101676 + 265005275101677.

It is an arithmetic number, because the mean of its divisors is an integer number (265005275101677).

Almost surely, 2530010550203353 is an apocalyptic number.

It is an amenable number.

530010550203353 is a deficient number, since it is larger than the sum of its proper divisors (1).

530010550203353 is an equidigital number, since it uses as much as digits as its factorization.

530010550203353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 101250, while the sum is 35.

The spelling of 530010550203353 in words is "five hundred thirty trillion, ten billion, five hundred fifty million, two hundred three thousand, three hundred fifty-three".