Base | Representation |
---|---|
bin | 111100010000010101011001… |
… | …0100100100111001110110111 |
3 | 2120111121111212112100021002201 |
4 | 1320200222302210213032313 |
5 | 1023432143101323001234 |
6 | 5115123252504245331 |
7 | 216431666343655303 |
oct | 17040526244471667 |
9 | 2514544775307081 |
10 | 530010550203319 |
11 | 143972237274819 |
12 | 4b53b718a70847 |
13 | 19997a1b7a22a3 |
14 | 94c490ca6cd03 |
15 | 4141bcda18314 |
hex | 1e20ab29273b7 |
530010550203319 has 2 divisors, whose sum is σ = 530010550203320. Its totient is φ = 530010550203318.
The previous prime is 530010550203289. The next prime is 530010550203353. The reversal of 530010550203319 is 913302055010035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 530010550203319 - 221 = 530010548106167 is a prime.
It is a super-2 number, since 2×5300105502033192 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530010550203919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265005275101659 + 265005275101660.
It is an arithmetic number, because the mean of its divisors is an integer number (265005275101660).
Almost surely, 2530010550203319 is an apocalyptic number.
530010550203319 is a deficient number, since it is larger than the sum of its proper divisors (1).
530010550203319 is an equidigital number, since it uses as much as digits as its factorization.
530010550203319 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60750, while the sum is 37.
The spelling of 530010550203319 in words is "five hundred thirty trillion, ten billion, five hundred fifty million, two hundred three thousand, three hundred nineteen".
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