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53001119 is a prime number
BaseRepresentation
bin1100101000101…
…1101110011111
310200201201212102
43022023232133
5102032013434
65131555315
71212334133
oct312135637
9120651772
1053001119
1127a10586
12158bbb3b
13ac99412
1470793c3
1549be07e
hex328bb9f

53001119 has 2 divisors, whose sum is σ = 53001120. Its totient is φ = 53001118.

The previous prime is 53001097. The next prime is 53001133. The reversal of 53001119 is 91110035.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53001119 is a prime.

It is a super-2 number, since 2×530011192 = 5618237230504322, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 53001119.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53001199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26500559 + 26500560.

It is an arithmetic number, because the mean of its divisors is an integer number (26500560).

Almost surely, 253001119 is an apocalyptic number.

53001119 is a deficient number, since it is larger than the sum of its proper divisors (1).

53001119 is an equidigital number, since it uses as much as digits as its factorization.

53001119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 135, while the sum is 20.

The square root of 53001119 is about 7280.1867421104. The cubic root of 53001119 is about 375.6312189782.

The spelling of 53001119 in words is "fifty-three million, one thousand, one hundred nineteen".