Base | Representation |
---|---|
bin | 11000000110100101000110… |
… | …00111110010101011110111 |
3 | 20221200000001122012000001121 |
4 | 30003102203013302223313 |
5 | 23421343343042131323 |
6 | 304421023514404411 |
7 | 14110212442242616 |
oct | 1403224307625367 |
9 | 227600048160047 |
10 | 53002633161463 |
11 | 15985321709a67 |
12 | 5b40322730707 |
13 | 2376185936a8b |
14 | d134ac0d587d |
15 | 61dac0634a5d |
hex | 3034a31f2af7 |
53002633161463 has 2 divisors, whose sum is σ = 53002633161464. Its totient is φ = 53002633161462.
The previous prime is 53002633161427. The next prime is 53002633161563. The reversal of 53002633161463 is 36416133620035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53002633161463 - 233 = 52994043226871 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53002633161403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26501316580731 + 26501316580732.
It is an arithmetic number, because the mean of its divisors is an integer number (26501316580732).
Almost surely, 253002633161463 is an apocalyptic number.
53002633161463 is a deficient number, since it is larger than the sum of its proper divisors (1).
53002633161463 is an equidigital number, since it uses as much as digits as its factorization.
53002633161463 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 699840, while the sum is 43.
Adding to 53002633161463 its reverse (36416133620035), we get a palindrome (89418766781498).
The spelling of 53002633161463 in words is "fifty-three trillion, two billion, six hundred thirty-three million, one hundred sixty-one thousand, four hundred sixty-three".
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