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530035374404897 is a prime number
BaseRepresentation
bin111100010000100000111101…
…0001101011011010100100001
32120111200212221120110100210222
41320201001322031123110201
51023433044421321424042
65115142520045132425
7216433535455130654
oct17041017215332441
92514625846410728
10530035374404897
11143981815948899
124b5444a655a115
131999a17677616a
1494c5bc593389b
1541426830622d2
hex1e2107a35b521

530035374404897 has 2 divisors, whose sum is σ = 530035374404898. Its totient is φ = 530035374404896.

The previous prime is 530035374404869. The next prime is 530035374405049. The reversal of 530035374404897 is 798404473530035.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 419029743086656 + 111005631318241 = 20470216^2 + 10535921^2 .

It is a cyclic number.

It is not a de Polignac number, because 530035374404897 - 218 = 530035374142753 is a prime.

It is not a weakly prime, because it can be changed into another prime (530035374404597) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265017687202448 + 265017687202449.

It is an arithmetic number, because the mean of its divisors is an integer number (265017687202449).

Almost surely, 2530035374404897 is an apocalyptic number.

It is an amenable number.

530035374404897 is a deficient number, since it is larger than the sum of its proper divisors (1).

530035374404897 is an equidigital number, since it uses as much as digits as its factorization.

530035374404897 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 152409600, while the sum is 62.

The spelling of 530035374404897 in words is "five hundred thirty trillion, thirty-five billion, three hundred seventy-four million, four hundred four thousand, eight hundred ninety-seven".