Base | Representation |
---|---|
bin | 110001010111010010… |
… | …101100000010110101 |
3 | 12001210221121111111100 |
4 | 301113102230002311 |
5 | 1332023023434331 |
6 | 40203314200313 |
7 | 3554330423520 |
oct | 612722540265 |
9 | 161727544440 |
10 | 53004124341 |
11 | 2052a4a0143 |
12 | a332b83099 |
13 | 4cc92695ac |
14 | 27cb6cbbb7 |
15 | 15a34a0ae6 |
hex | c574ac0b5 |
53004124341 has 48 divisors (see below), whose sum is σ = 88208640000. Its totient is φ = 30042986400.
The previous prime is 53004124333. The next prime is 53004124363. The reversal of 53004124341 is 14342140035.
It is a happy number.
53004124341 is a `hidden beast` number, since 5 + 300 + 4 + 12 + 4 + 341 = 666.
It is not a de Polignac number, because 53004124341 - 23 = 53004124333 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53004124241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 7064410 + ... + 7071908.
It is an arithmetic number, because the mean of its divisors is an integer number (1837680000).
Almost surely, 253004124341 is an apocalyptic number.
It is an amenable number.
53004124341 is a deficient number, since it is larger than the sum of its proper divisors (35204515659).
53004124341 is a wasteful number, since it uses less digits than its factorization.
53004124341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8406 (or 8403 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 27.
Adding to 53004124341 its reverse (14342140035), we get a palindrome (67346264376).
The spelling of 53004124341 in words is "fifty-three billion, four million, one hundred twenty-four thousand, three hundred forty-one".
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