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53004456013 is a prime number
BaseRepresentation
bin110001010111010011…
…111101000001001101
312001210222020100110111
4301113103331001031
51332023120043023
640203325240021
73554333304505
oct612723750115
9161728210414
1053004456013
112052a6a7353
12a333103011
134cc9354552
1427cb776a05
1515a351900d
hexc574fd04d

53004456013 has 2 divisors, whose sum is σ = 53004456014. Its totient is φ = 53004456012.

The previous prime is 53004455989. The next prime is 53004456097. The reversal of 53004456013 is 31065440035.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 40281292804 + 12723163209 = 200702^2 + 112797^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53004456013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53004466013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26502228006 + 26502228007.

It is an arithmetic number, because the mean of its divisors is an integer number (26502228007).

Almost surely, 253004456013 is an apocalyptic number.

It is an amenable number.

53004456013 is a deficient number, since it is larger than the sum of its proper divisors (1).

53004456013 is an equidigital number, since it uses as much as digits as its factorization.

53004456013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 53004456013 its reverse (31065440035), we get a palindrome (84069896048).

The spelling of 53004456013 in words is "fifty-three billion, four million, four hundred fifty-six thousand, thirteen".