Base | Representation |
---|---|
bin | 1111011011010011001… |
… | …11111100111100000101 |
3 | 1212200011022100020221012 |
4 | 13231221213330330011 |
5 | 32141022040331214 |
6 | 1043300352332005 |
7 | 53203131441215 |
oct | 7555147747405 |
9 | 1780138306835 |
10 | 530053058309 |
11 | 194881150a75 |
12 | 86889844005 |
13 | 3aca34cc308 |
14 | 1b924720245 |
15 | dbc423d03e |
hex | 7b699fcf05 |
530053058309 has 2 divisors, whose sum is σ = 530053058310. Its totient is φ = 530053058308.
The previous prime is 530053058261. The next prime is 530053058323. The reversal of 530053058309 is 903850350035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 530052434209 + 624100 = 728047^2 + 790^2 .
It is a cyclic number.
It is not a de Polignac number, because 530053058309 - 220 = 530052009733 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530053058329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265026529154 + 265026529155.
It is an arithmetic number, because the mean of its divisors is an integer number (265026529155).
Almost surely, 2530053058309 is an apocalyptic number.
It is an amenable number.
530053058309 is a deficient number, since it is larger than the sum of its proper divisors (1).
530053058309 is an equidigital number, since it uses as much as digits as its factorization.
530053058309 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243000, while the sum is 41.
The spelling of 530053058309 in words is "five hundred thirty billion, fifty-three million, fifty-eight thousand, three hundred nine".
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