Base | Representation |
---|---|
bin | 111100010000101001011010… |
… | …1001110010001100111110111 |
3 | 2120111202121211212102022202221 |
4 | 1320201102311032101213313 |
5 | 1023433344124323232442 |
6 | 5115155123042143211 |
7 | 216435050646132256 |
oct | 17041226516214767 |
9 | 2514677755368687 |
10 | 530053544352247 |
11 | 14398949a357203 |
12 | 4b547b17651b07 |
13 | 1999bab0c6aab6 |
14 | 94c6a2ab5c79d |
15 | 4142d982da467 |
hex | 1e214b53919f7 |
530053544352247 has 2 divisors, whose sum is σ = 530053544352248. Its totient is φ = 530053544352246.
The previous prime is 530053544352217. The next prime is 530053544352253. The reversal of 530053544352247 is 742253445350035.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-530053544352247 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 530053544352194 and 530053544352203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530053544352217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265026772176123 + 265026772176124.
It is an arithmetic number, because the mean of its divisors is an integer number (265026772176124).
Almost surely, 2530053544352247 is an apocalyptic number.
530053544352247 is a deficient number, since it is larger than the sum of its proper divisors (1).
530053544352247 is an equidigital number, since it uses as much as digits as its factorization.
530053544352247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30240000, while the sum is 52.
The spelling of 530053544352247 in words is "five hundred thirty trillion, fifty-three billion, five hundred forty-four million, three hundred fifty-two thousand, two hundred forty-seven".
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