Base | Representation |
---|---|
bin | 111100010000101001110001… |
… | …1100010001001010001000111 |
3 | 2120111202200212000102000100011 |
4 | 1320201103203202021101013 |
5 | 1023433402222224002324 |
6 | 5115155332115131051 |
7 | 216435106132160431 |
oct | 17041234342112107 |
9 | 2514680760360304 |
10 | 530054321312839 |
11 | 1439898589911a4 |
12 | 4b5480b38a3a87 |
13 | 1999bba5c14cab |
14 | 94c6aa200b651 |
15 | 4142de1610c94 |
hex | 1e214e3889447 |
530054321312839 has 2 divisors, whose sum is σ = 530054321312840. Its totient is φ = 530054321312838.
The previous prime is 530054321312827. The next prime is 530054321312899. The reversal of 530054321312839 is 938213123450035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 530054321312839 - 237 = 529916882359367 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 530054321312792 and 530054321312801.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530054321312899) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265027160656419 + 265027160656420.
It is an arithmetic number, because the mean of its divisors is an integer number (265027160656420).
Almost surely, 2530054321312839 is an apocalyptic number.
530054321312839 is a deficient number, since it is larger than the sum of its proper divisors (1).
530054321312839 is an equidigital number, since it uses as much as digits as its factorization.
530054321312839 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2332800, while the sum is 49.
The spelling of 530054321312839 in words is "five hundred thirty trillion, fifty-four billion, three hundred twenty-one million, three hundred twelve thousand, eight hundred thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •