Base | Representation |
---|---|
bin | 111100010000101001110001… |
… | …1100010001001011001000111 |
3 | 2120111202200212000102001001010 |
4 | 1320201103203202021121013 |
5 | 1023433402222224011401 |
6 | 5115155332115133303 |
7 | 216435106132162062 |
oct | 17041234342113107 |
9 | 2514680760361033 |
10 | 530054321313351 |
11 | 14398985899161a |
12 | 4b5480b38a4233 |
13 | 1999bba5c152b3 |
14 | 94c6aa200b8d9 |
15 | 4142de1610ed6 |
hex | 1e214e3889647 |
530054321313351 has 32 divisors (see below), whose sum is σ = 713644047221760. Its totient is φ = 349930169132544.
The previous prime is 530054321313259. The next prime is 530054321313371. The reversal of 530054321313351 is 153313123450035.
It is not a de Polignac number, because 530054321313351 - 29 = 530054321312839 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530054321313371) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 652870180 + ... + 653681558.
It is an arithmetic number, because the mean of its divisors is an integer number (22301376475680).
Almost surely, 2530054321313351 is an apocalyptic number.
530054321313351 is a deficient number, since it is larger than the sum of its proper divisors (183589725908409).
530054321313351 is a wasteful number, since it uses less digits than its factorization.
530054321313351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 815415.
The product of its (nonzero) digits is 243000, while the sum is 39.
Adding to 530054321313351 its reverse (153313123450035), we get a palindrome (683367444763386).
The spelling of 530054321313351 in words is "five hundred thirty trillion, fifty-four billion, three hundred twenty-one million, three hundred thirteen thousand, three hundred fifty-one".
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