Base | Representation |
---|---|
bin | 1111011011010011100… |
… | …00111000101111010011 |
3 | 1212200011110202020200102 |
4 | 13231221300320233103 |
5 | 32141023140303103 |
6 | 1043300514443015 |
7 | 53203160364404 |
oct | 7555160705723 |
9 | 1780143666612 |
10 | 530055400403 |
11 | 194882500691 |
12 | 8688a59346b |
13 | 3aca3b3c379 |
14 | 1b924b6d9ab |
15 | dbc4551e88 |
hex | 7b69c38bd3 |
530055400403 has 2 divisors, whose sum is σ = 530055400404. Its totient is φ = 530055400402.
The previous prime is 530055400367. The next prime is 530055400439. The reversal of 530055400403 is 304004550035.
It is a balanced prime because it is at equal distance from previous prime (530055400367) and next prime (530055400439).
It is a cyclic number.
It is not a de Polignac number, because 530055400403 - 218 = 530055138259 is a prime.
It is not a weakly prime, because it can be changed into another prime (530055400003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265027700201 + 265027700202.
It is an arithmetic number, because the mean of its divisors is an integer number (265027700202).
Almost surely, 2530055400403 is an apocalyptic number.
530055400403 is a deficient number, since it is larger than the sum of its proper divisors (1).
530055400403 is an equidigital number, since it uses as much as digits as its factorization.
530055400403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18000, while the sum is 29.
Adding to 530055400403 its reverse (304004550035), we get a palindrome (834059950438).
The spelling of 530055400403 in words is "five hundred thirty billion, fifty-five million, four hundred thousand, four hundred three".
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