Base | Representation |
---|---|
bin | 111100010001000000100101… |
… | …0111010010010011110110100 |
3 | 2120111221101021110002011101222 |
4 | 1320202001022322102132310 |
5 | 1023440203024341214130 |
6 | 5115234032205405512 |
7 | 216441461646043121 |
oct | 17042011272223664 |
9 | 2514841243064358 |
10 | 530103300335540 |
11 | 1439a8602302958 |
12 | 4b5556a2869898 |
13 | 199a36b02b1629 |
14 | 94c91caccd748 |
15 | 414430b52dce5 |
hex | 1e2204ae927b4 |
530103300335540 has 48 divisors (see below), whose sum is σ = 1114417469471040. Its totient is φ = 211812667292160.
The previous prime is 530103300335533. The next prime is 530103300335563. The reversal of 530103300335540 is 45533003301035.
It is a self number, because there is not a number n which added to its sum of digits gives 530103300335540.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 405983564 + ... + 407287196.
It is an arithmetic number, because the mean of its divisors is an integer number (23217030613980).
Almost surely, 2530103300335540 is an apocalyptic number.
It is an amenable number.
530103300335540 is an abundant number, since it is smaller than the sum of its proper divisors (584314169135500).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
530103300335540 is a wasteful number, since it uses less digits than its factorization.
530103300335540 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1325552 (or 1325550 counting only the distinct ones).
The product of its (nonzero) digits is 121500, while the sum is 35.
Adding to 530103300335540 its reverse (45533003301035), we get a palindrome (575636303636575).
The spelling of 530103300335540 in words is "five hundred thirty trillion, one hundred three billion, three hundred million, three hundred thirty-five thousand, five hundred forty".
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