Base | Representation |
---|---|
bin | 111100010001000000100101… |
… | …1000100111000001001010111 |
3 | 2120111221101021122022011222020 |
4 | 1320202001023010320021113 |
5 | 1023440203031044030010 |
6 | 5115234032345104223 |
7 | 216441462011453436 |
oct | 17042011304701127 |
9 | 2514841248264866 |
10 | 530103303111255 |
11 | 1439a8603929335 |
12 | 4b5556a3788073 |
13 | 199a36b0a43b73 |
14 | 94c91cb41311d |
15 | 414430b8cb470 |
hex | 1e2204b138257 |
530103303111255 has 32 divisors (see below), whose sum is σ = 867911869693440. Its totient is φ = 276139897219200.
The previous prime is 530103303111253. The next prime is 530103303111269. The reversal of 530103303111255 is 552111303301035.
It is not a de Polignac number, because 530103303111255 - 21 = 530103303111253 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530103303111253) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15408430 + ... + 36022580.
It is an arithmetic number, because the mean of its divisors is an integer number (27122245927920).
Almost surely, 2530103303111255 is an apocalyptic number.
530103303111255 is a deficient number, since it is larger than the sum of its proper divisors (337808566582185).
530103303111255 is a wasteful number, since it uses less digits than its factorization.
530103303111255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20654071.
The product of its (nonzero) digits is 20250, while the sum is 33.
The spelling of 530103303111255 in words is "five hundred thirty trillion, one hundred three billion, three hundred three million, one hundred eleven thousand, two hundred fifty-five".
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