Base | Representation |
---|---|
bin | 111100010001000000100101… |
… | …1000100111000010110100101 |
3 | 2120111221101021122022020010120 |
4 | 1320202001023010320112211 |
5 | 1023440203031044041401 |
6 | 5115234032345112153 |
7 | 216441462011456055 |
oct | 17042011304702645 |
9 | 2514841248266116 |
10 | 530103303112101 |
11 | 1439a8603929a34 |
12 | 4b5556a3788659 |
13 | 199a36b0a44374 |
14 | 94c91cb413565 |
15 | 414430b8cb836 |
hex | 1e2204b1385a5 |
530103303112101 has 16 divisors (see below), whose sum is σ = 707299741591296. Its totient is φ = 353154618818496.
The previous prime is 530103303112073. The next prime is 530103303112109. The reversal of 530103303112101 is 101211303301035.
It is a happy number.
It is not a de Polignac number, because 530103303112101 - 210 = 530103303111077 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530103303112109) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14136951 + ... + 35497323.
It is an arithmetic number, because the mean of its divisors is an integer number (44206233849456).
Almost surely, 2530103303112101 is an apocalyptic number.
It is an amenable number.
530103303112101 is a deficient number, since it is larger than the sum of its proper divisors (177196438479195).
530103303112101 is a wasteful number, since it uses less digits than its factorization.
530103303112101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21366172.
The product of its (nonzero) digits is 810, while the sum is 24.
Adding to 530103303112101 its reverse (101211303301035), we get a palindrome (631314606413136).
The spelling of 530103303112101 in words is "five hundred thirty trillion, one hundred three billion, three hundred three million, one hundred twelve thousand, one hundred one".
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