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530103303113177 is a prime number
BaseRepresentation
bin111100010001000000100101…
…1000100111000100111011001
32120111221101021122022021121102
41320202001023010320213121
51023440203031044110202
65115234032345121145
7216441462011462153
oct17042011304704731
92514841248267542
10530103303113177
111439a860392a822
124b5556a37891b5
13199a36b0a449c1
1494c91cb413ad3
15414430b8cbd02
hex1e2204b1389d9

530103303113177 has 2 divisors, whose sum is σ = 530103303113178. Its totient is φ = 530103303113176.

The previous prime is 530103303113143. The next prime is 530103303113213. The reversal of 530103303113177 is 771311303301035.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 499443339436441 + 30659963676736 = 22348229^2 + 5537144^2 .

It is a cyclic number.

It is not a de Polignac number, because 530103303113177 - 28 = 530103303112921 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 530103303113177.

It is not a weakly prime, because it can be changed into another prime (530103303113107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265051651556588 + 265051651556589.

It is an arithmetic number, because the mean of its divisors is an integer number (265051651556589).

Almost surely, 2530103303113177 is an apocalyptic number.

It is an amenable number.

530103303113177 is a deficient number, since it is larger than the sum of its proper divisors (1).

530103303113177 is an equidigital number, since it uses as much as digits as its factorization.

530103303113177 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 59535, while the sum is 38.

The spelling of 530103303113177 in words is "five hundred thirty trillion, one hundred three billion, three hundred three million, one hundred thirteen thousand, one hundred seventy-seven".