Base | Representation |
---|---|
bin | 110001010111101101… |
… | …011000111110110011 |
3 | 12001211102210010102102 |
4 | 301113231120332303 |
5 | 1332031321433042 |
6 | 40204124211015 |
7 | 3554444056232 |
oct | 612755307663 |
9 | 161742703372 |
10 | 53011124147 |
11 | 20533441203 |
12 | a335399a6b |
13 | 4cca84a6a7 |
14 | 27cc5d0b19 |
15 | 15a3dd4b32 |
hex | c57b58fb3 |
53011124147 has 2 divisors, whose sum is σ = 53011124148. Its totient is φ = 53011124146.
The previous prime is 53011124137. The next prime is 53011124149. The reversal of 53011124147 is 74142111035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53011124147 - 26 = 53011124083 is a prime.
Together with 53011124149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (53011124149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26505562073 + 26505562074.
It is an arithmetic number, because the mean of its divisors is an integer number (26505562074).
Almost surely, 253011124147 is an apocalyptic number.
53011124147 is a deficient number, since it is larger than the sum of its proper divisors (1).
53011124147 is an equidigital number, since it uses as much as digits as its factorization.
53011124147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3360, while the sum is 29.
The spelling of 53011124147 in words is "fifty-three billion, eleven million, one hundred twenty-four thousand, one hundred forty-seven".
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