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53012625501607 is a prime number
BaseRepresentation
bin11000000110110111101101…
…01101100010110110100111
320221200221212000112110211121
430003123312231202312213
523422024324112022412
6304425355225114411
714111015164602622
oct1403336655426647
9227627760473747
1053012625501607
111598958a072012
125b42251028a07
1323770b8b71895
14d13b79222db9
1561dea79cd107
hex3036f6b62da7

53012625501607 has 2 divisors, whose sum is σ = 53012625501608. Its totient is φ = 53012625501606.

The previous prime is 53012625501599. The next prime is 53012625501611. The reversal of 53012625501607 is 70610552621035.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 53012625501607 - 23 = 53012625501599 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53012625501007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26506312750803 + 26506312750804.

It is an arithmetic number, because the mean of its divisors is an integer number (26506312750804).

Almost surely, 253012625501607 is an apocalyptic number.

53012625501607 is a deficient number, since it is larger than the sum of its proper divisors (1).

53012625501607 is an equidigital number, since it uses as much as digits as its factorization.

53012625501607 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 378000, while the sum is 43.

The spelling of 53012625501607 in words is "fifty-three trillion, twelve billion, six hundred twenty-five million, five hundred one thousand, six hundred seven".