Base | Representation |
---|---|
bin | 11000000110110111101101… |
… | …01101100010110110100111 |
3 | 20221200221212000112110211121 |
4 | 30003123312231202312213 |
5 | 23422024324112022412 |
6 | 304425355225114411 |
7 | 14111015164602622 |
oct | 1403336655426647 |
9 | 227627760473747 |
10 | 53012625501607 |
11 | 1598958a072012 |
12 | 5b42251028a07 |
13 | 23770b8b71895 |
14 | d13b79222db9 |
15 | 61dea79cd107 |
hex | 3036f6b62da7 |
53012625501607 has 2 divisors, whose sum is σ = 53012625501608. Its totient is φ = 53012625501606.
The previous prime is 53012625501599. The next prime is 53012625501611. The reversal of 53012625501607 is 70610552621035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53012625501607 - 23 = 53012625501599 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53012625501007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26506312750803 + 26506312750804.
It is an arithmetic number, because the mean of its divisors is an integer number (26506312750804).
Almost surely, 253012625501607 is an apocalyptic number.
53012625501607 is a deficient number, since it is larger than the sum of its proper divisors (1).
53012625501607 is an equidigital number, since it uses as much as digits as its factorization.
53012625501607 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 378000, while the sum is 43.
The spelling of 53012625501607 in words is "fifty-three trillion, twelve billion, six hundred twenty-five million, five hundred one thousand, six hundred seven".
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