Base | Representation |
---|---|
bin | 1001110111111110… |
… | …01111011101111111 |
3 | 111200110112002122122 |
4 | 10323333033131333 |
5 | 41324124321341 |
6 | 2234015233155 |
7 | 245242111652 |
oct | 47377173577 |
9 | 14613462578 |
10 | 5301401471 |
11 | 2280559433 |
12 | 103b5187bb |
13 | 66642a562 |
14 | 38411b899 |
15 | 21064094b |
hex | 13bfcf77f |
5301401471 has 2 divisors, whose sum is σ = 5301401472. Its totient is φ = 5301401470.
The previous prime is 5301401467. The next prime is 5301401503. The reversal of 5301401471 is 1741041035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5301401471 - 22 = 5301401467 is a prime.
It is a super-3 number, since 3×53014014713 (a number of 30 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5301401471.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5301401461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2650700735 + 2650700736.
It is an arithmetic number, because the mean of its divisors is an integer number (2650700736).
Almost surely, 25301401471 is an apocalyptic number.
5301401471 is a deficient number, since it is larger than the sum of its proper divisors (1).
5301401471 is an equidigital number, since it uses as much as digits as its factorization.
5301401471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1680, while the sum is 26.
The square root of 5301401471 is about 72810.7235989315. The cubic root of 5301401471 is about 1743.6670659271.
The spelling of 5301401471 in words is "five billion, three hundred one million, four hundred one thousand, four hundred seventy-one".
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