530143531 has 2 divisors, whose sum is σ = 530143532. Its totient is φ = 530143530.

The previous prime is 530143513. The next prime is 530143543. The reversal of 530143531 is 135341035.

Together with previous prime (530143513) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 530143531 - 2⁵ = 530143499 is a prime.

It is a super-2 number, since 2×530143531² = 562104326922295922, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 530143496 and 530143505.

It is not a weakly prime, because it can be changed into another prime (530143501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265071765 + 265071766.

It is an arithmetic number, because the mean of its divisors is an integer number (265071766).

Almost surely, 2^530143531 is an apocalyptic number.

530143531 is a deficient number, since it is larger than the sum of its proper divisors (1).

530143531 is an equidigital number, since it uses as much as digits as its factorization.

530143531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2700, while the sum is 25.

The square root of 530143531 is about 23024.8459495389. The cubic root of 530143531 is about 809.3402802814.

Adding to 530143531 its reverse (135341035), we get a palindrome (665484566).

The spelling of 530143531 in words is "five hundred thirty million, one hundred forty-three thousand, five hundred thirty-one".