Base | Representation |
---|---|
bin | 110001010111111100… |
… | …101001010001001001 |
3 | 12001211201022021211201 |
4 | 301113330221101021 |
5 | 1332033332414032 |
6 | 40204350024201 |
7 | 3554523052603 |
oct | 612774512111 |
9 | 161751267751 |
10 | 53015123017 |
11 | 2053572265a |
12 | a3367a8061 |
13 | 4ccb61a89c |
14 | 27ccd52173 |
15 | 15a44248e7 |
hex | c57f29449 |
53015123017 has 2 divisors, whose sum is σ = 53015123018. Its totient is φ = 53015123016.
The previous prime is 53015122987. The next prime is 53015123041. The reversal of 53015123017 is 71032151035.
53015123017 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 52711108921 + 304014096 = 229589^2 + 17436^2 .
It is a cyclic number.
It is not a de Polignac number, because 53015123017 - 227 = 52880905289 is a prime.
It is not a weakly prime, because it can be changed into another prime (53015123047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26507561508 + 26507561509.
It is an arithmetic number, because the mean of its divisors is an integer number (26507561509).
Almost surely, 253015123017 is an apocalyptic number.
It is an amenable number.
53015123017 is a deficient number, since it is larger than the sum of its proper divisors (1).
53015123017 is an equidigital number, since it uses as much as digits as its factorization.
53015123017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3150, while the sum is 28.
The spelling of 53015123017 in words is "fifty-three billion, fifteen million, one hundred twenty-three thousand, seventeen".
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