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53015123041 is a prime number
BaseRepresentation
bin110001010111111100…
…101001010001100001
312001211201022021212121
4301113330221101201
51332033332414131
640204350024241
73554523052636
oct612774512141
9161751267777
1053015123041
1120535722681
12a3367a8081
134ccb61a8ba
1427ccd5218d
1515a4424911
hexc57f29461

53015123041 has 2 divisors, whose sum is σ = 53015123042. Its totient is φ = 53015123040.

The previous prime is 53015123017. The next prime is 53015123047. The reversal of 53015123041 is 14032151035.

It is a happy number.

53015123041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36764227600 + 16250895441 = 191740^2 + 127479^2 .

It is a cyclic number.

It is not a de Polignac number, because 53015123041 - 215 = 53015090273 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53015122997 and 53015123015.

It is not a weakly prime, because it can be changed into another prime (53015123047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26507561520 + 26507561521.

It is an arithmetic number, because the mean of its divisors is an integer number (26507561521).

Almost surely, 253015123041 is an apocalyptic number.

It is an amenable number.

53015123041 is a deficient number, since it is larger than the sum of its proper divisors (1).

53015123041 is an equidigital number, since it uses as much as digits as its factorization.

53015123041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 53015123041 its reverse (14032151035), we get a palindrome (67047274076).

The spelling of 53015123041 in words is "fifty-three billion, fifteen million, one hundred twenty-three thousand, forty-one".