Base | Representation |
---|---|
bin | 111100010001010110111010… |
… | …1000100010010111101011011 |
3 | 2120112002222001022001102020102 |
4 | 1320202231311010102331123 |
5 | 1023441444231033223032 |
6 | 5115312042325250015 |
7 | 216445110151400345 |
oct | 17042556504227533 |
9 | 2515088038042212 |
10 | 530151252242267 |
11 | 143a16979970137 |
12 | 4b562a4586390b |
13 | 199a8082938736 |
14 | 94cb659606295 |
15 | 41456b61b1362 |
hex | 1e22b75112f5b |
530151252242267 has 2 divisors, whose sum is σ = 530151252242268. Its totient is φ = 530151252242266.
The previous prime is 530151252242257. The next prime is 530151252242317. The reversal of 530151252242267 is 762242252151035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 530151252242267 - 26 = 530151252242203 is a prime.
It is a super-2 number, since 2×5301512522422672 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (530151252242257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265075626121133 + 265075626121134.
It is an arithmetic number, because the mean of its divisors is an integer number (265075626121134).
Almost surely, 2530151252242267 is an apocalyptic number.
530151252242267 is a deficient number, since it is larger than the sum of its proper divisors (1).
530151252242267 is an equidigital number, since it uses as much as digits as its factorization.
530151252242267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016000, while the sum is 47.
The spelling of 530151252242267 in words is "five hundred thirty trillion, one hundred fifty-one billion, two hundred fifty-two million, two hundred forty-two thousand, two hundred sixty-seven".
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