Base | Representation |
---|---|
bin | 110001010111111101… |
… | …010101001111001001 |
3 | 12001211201122102212221 |
4 | 301113331111033021 |
5 | 1332033404144423 |
6 | 40204353534041 |
7 | 3554524432633 |
oct | 612775251711 |
9 | 161751572787 |
10 | 53015303113 |
11 | 205358359a3 |
12 | a336874321 |
13 | 4ccb681856 |
14 | 27ccd9ba53 |
15 | 15a445ce5d |
hex | c57f553c9 |
53015303113 has 2 divisors, whose sum is σ = 53015303114. Its totient is φ = 53015303112.
The previous prime is 53015303083. The next prime is 53015303123. The reversal of 53015303113 is 31130351035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51668926864 + 1346376249 = 227308^2 + 36693^2 .
It is a cyclic number.
It is not a de Polignac number, because 53015303113 - 233 = 44425368521 is a prime.
It is not a weakly prime, because it can be changed into another prime (53015303123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26507651556 + 26507651557.
It is an arithmetic number, because the mean of its divisors is an integer number (26507651557).
Almost surely, 253015303113 is an apocalyptic number.
It is an amenable number.
53015303113 is a deficient number, since it is larger than the sum of its proper divisors (1).
53015303113 is an equidigital number, since it uses as much as digits as its factorization.
53015303113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2025, while the sum is 25.
Adding to 53015303113 its reverse (31130351035), we get a palindrome (84145654148).
The spelling of 53015303113 in words is "fifty-three billion, fifteen million, three hundred three thousand, one hundred thirteen".
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